How many moles are present in 4.9g of H2SO4
barish95644:
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Answers
Answered by
67
see... I mole of sulfuric acid= 98 gm
98 gm corresponds to 1 gram molecule of the given compound (h2so4)
1 gm corresponds to 1/98 gram molecules
4.9 gm corresponds to 4.9/98 gram molecules = 1/20 gram molecules = 0.05 gram molecules (Ans.)
98 gm corresponds to 1 gram molecule of the given compound (h2so4)
1 gm corresponds to 1/98 gram molecules
4.9 gm corresponds to 4.9/98 gram molecules = 1/20 gram molecules = 0.05 gram molecules (Ans.)
Answered by
15
Answer:
Explanation:
no of moles=(mass)/molar mass=4.9/98==0.05, please mark it brainiest
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