Question

how many moles are present in 400 gm of NaoH​

Answer 1

To find:-

☆Number of moles present in 400g of NaOH(Sodium-hydroxide)

Solution:-

•Atomic mass of Sodium=23u

•Atomic mass of oxygen=16u

•Atomic mass of hydrogen=1u

Thus,molecular mass of NaOH(sodium-hydroxide)

=>23+16+1

=>40u

Since molecular mass of NaOH is 40u,thus it's molar mass is 40g.

Now,we know that:-

No of moles=Given mass/Molar mass

=>400/40

=>10 moles

Thus,10 moles are present in 400g of NaOH

Answer 2

Given:-

• 400gm of NaoH

To Find:-

• Number of Moles.

FORMULAE USED:-

• ${\boxed{\rm{No.\:of\:Mole = \dfrac{Given\:mass}{Molar\:Mass}}}}$

Now,

Atomis Mass of NaoH

Na = 23

O = 16

H = 1

So,

NaoH = 23 + 16 + 1 = 40u

Hence, The GAM of NaoH is 40g

Therefore

$\implies\rm{No\:of\:Moles = \dfrac{Given\:mass}{Molar\:mass}$

$\implies\rm{No\:of\:Moles = \dfrac{400}{40}}$

$\implies\rm{No.\:of\:Mole = 10Mole}$.

Hence, No. of Mole Present in 400g of NaoH is 10.

Table of atomic mass of Some Element.

$\begin{array}{|c|c|} \cline{1-2} Element & Atomic mass\\ \cline{1 - 2} Hydrogen & 1 \\ \cline{1 - 2} Carbon & 12 \\ \cline{1 - 2} \\Oxygen & 16 \\ \cline{1 - 2} Sodium & 23 \\ \cline{1 - 2} Magnesium & 24 \\ \cline{ 1 - 2} Sulphur & 32 \\ \cline{1 - 2} chlorine & 35.5 \\ \cline{ 1 - 2} Calcium & 40 \\ \cline{ 1 - 2}\end{array}$