Question

How many moles are present in 5.3 g of anhydrous sodium carbonate

Answer 1

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Mass of sodium carbonate .

Molar mass of Na2CO3 = 23×2 + 12 + 16×3 = 105g/mol

Moles of Na2CO3 =mass/ molar mass

Moles of Na2CO3 =5.3/105

Moles of Na2CO3 =0.05mol


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Answer 2

Answer:

Explanation:

Molar mass of sodium carbonate = 106 g

Amount given =5.3 g

No. Of moles = 5.3 ÷ 106 = 0.05 g

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