How many moles are present in 9.033*10^24atoms of heelium?
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moles are present in 9.033*10^24atoms of heelium
9.033*10^24/6.022×10^23
=1.5×10
=15 moles
9.033*10^24/6.022×10^23
=1.5×10
=15 moles
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