How many moles are present in 9.8 gram sulphuric acid
Answers
Answered by
1
1.2004
⋅
10
23
atoms / mol H
6.022
⋅
10
22
atoms / mol S
2.4088
⋅
10
23
atoms / mol O*
Explanation:
The molar mass of
H
2
S
O
4
is 98 g/mol.
For H:
9.8
g
H
2
S
O
4
(
1
m
o
l
H
2
S
O
4
98
g
H
2
S
O
4
)
(
2
m
o
l
H
1
m
o
l
H
2
S
O
4
)
(
6.022
⋅
10
23
a
t
m
s
1
m
o
l
H
)
=
1.2004
⋅
10
23
atoms / mol H
For S:
9.8
g
H
2
S
O
4
(
1
m
o
l
H
2
S
O
4
98
g
H
2
S
O
4
)
(
1
m
o
l
S
1
m
o
l
H
2
S
O
4
)
(
6.022
⋅
10
23
a
t
m
s
1
m
o
l
S
)
=
6.022
⋅
10
22
atoms / mol S
For O:
9.8
g
H
2
S
O
4
(
1
m
o
l
H
2
S
O
4
98
g
H
2
S
O
4
)
(
4
m
o
l
O
1
m
o
l
H
2
S
O
4
)
(
6.022
⋅
10
23
a
t
m
s
1
m
o
l
O
)
=
2.4088
⋅
10
23
atoms / mol O
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