Question

how many moles are required to prepare 40g of H2SO4 ? with solution and data.
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Answer 1

Answer:

the reaction is:

H2SO4 + 2NaOH =Na2SO4 + 2H2O

one mole of sulphuric acid reacts with two moles of sodium hyroxide

to give one mole of sodium sulphate and two moles of water.

Molecular weight of NaOH is 40 —— one mole weights 40 g

Molecular weight of sulphuric acid is 98——one mole weights 98 g

According to the formula, to neutralize 40 g of NaOH (one mole) you need half a mole of H2SO4 i.e. 98/2= 49 g of acid