Question

how many moles are required to prepare 40gm of H2SO4​

Answer 1

Answer:

0.408 mol

Explanation:

Since, 1 mole contains 98gm of H2SO4

Molar Mass of H2SO4 ≈ 98 g/mol

Therefore, 40 gm of H2SO4 will have 40/98 mol ≈ 0.408 mol.

Answer 2

MOLES -

• Unit of measuring small entities such as atoms, molecules, and other particles.
• Defined as the number of atoms present in 12g of a carbon atom.
• It is calculated as the ratio of weight by the molecular weight of the compound.
• In the given compound of sulphuric acid,

Molecular weight = 98g

Given weight = 40g

Moles(n) = $\frac{40}{98}$

n = 0.41 moles

• 0.41 moles are required to prepare 40gm of sulphuric acid.