how many moles are required to prepere 40mg of H2so4
Answers
Answer:
MOLES -
•Unit of measuring small entities such as atoms, molecules, and other particles.
•Defined as the number of atoms present in 12g of a carbon atom.
•It is calculated as the ratio of weight by the molecular weight of the compound.
•In the given compound of sulphuric acid
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Molecular weight = 98g
Molecular weight = 98gGiven weight = 40g
n = 0.41 moles
∴0.41 moles are required to prepare 40gm of sulphuric acid.
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Answer:
0.4 mmoles of is required to prepare 40 mg of .
Explanation:
Given mass = 40 mg = g
Molar mass of H = 1 g/mol
Molar mass of S = 32 g/mol
Molar mass of O = 16 g/mol
⇒Molar mass of = (2 × 1) + (1 × 32) + (4 × 16) = 98 g/mol
Number of moles = Given mass ÷ molar mass
= = 0.0004 moles = 0.4 mmoles
Therefore 0.4 mmoles of is required to prepare 40 mg of .