Chemistry, asked by assadkhanchandioc43, 18 days ago

how many moles are required to prepere 40mg of H2so4​

Answers

Answered by Anonymous
0

Answer:

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MOLES -

•Unit of measuring small entities such as atoms, molecules, and other particles.

•Defined as the number of atoms present in 12g of a carbon atom.

•It is calculated as the ratio of weight by the molecular weight of the compound.

•In the given compound of sulphuric acid

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Molecular weight = 98g

Molecular weight = 98gGiven weight = 40g

 \tt \: Moles(n) =  \frac{40}{98}  \\

n = 0.41 moles

0.41 moles are required to prepare 40gm of sulphuric acid.

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Answered by aparnaappu8547
0

Answer:

0.4 mmoles of H_{2} SO_{4} is required to prepare 40 mg of H_{2} SO_{4}.

Explanation:

Given mass = 40 mg = 40*10^{-3} g

Molar mass of H = 1 g/mol

Molar mass of S = 32 g/mol

Molar mass of O = 16 g/mol

⇒Molar mass of H_{2} SO_{4} = (2 × 1) + (1 × 32) + (4 × 16) = 98 g/mol

Number of moles = Given mass ÷ molar mass

                             = \frac{40*10^{-3} }{98} = 0.0004 moles = 0.4 mmoles

Therefore 0.4 mmoles of H_{2} SO_{4} is required to prepare 40 mg of H_{2} SO_{4}.

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