Chemistry, asked by Azia, 1 year ago

How many moles are there in 458 grams of Na2sO4?

Answers

Answered by Shilpakarpagam
25
Molecular weight of Na2SO4 = 23×2+32×1+16×4=142g
Given weight=458g
No of moles=Given weight/Gram molecular weight .
No of moles=458/142=3 moles.
There are 3 moles in 458 grams of Na2SO4.
Answered by zumba12
7

Given:

Mass of Na_2SO_4 = 458 g

To find:

Number of moles in 458 g of Na_2SO_4 = ?

Formula to be used:

Number of moles = \frac{Given mass}{Molar mass}

Calculation:

To calculate the molar mass of Na_2SO_4, the mass of individual element present in the compound must be known:

Atomic mass of Na = 23. As 2 atoms of sodium are present 2× 23 = 46

Atomic mass of S = 32

Atomic mass of O = 16. As 4 Oxygen atoms are present 4×16 = 64

Thus the Molar mass of Na_2SO_4 = 46+32+64 = 142g/mol

As the given mass as well as molar mass is known, number of moles can be calculated as follows:

Number of moles = \frac{458}{142} = 3.22 moles

Conclusion:

Thus it is inferred that 458g of Na_2SO_4contains 3.22 moles

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