Question

how many moles are there in 49g of pure sulphuric acid h2so4

Answer 1

Molar mass of H2SO4 = 98 g/mol

Number of moles of H2SO4 in 49 g = 49/98 = 0.5 moles

Hence, 0.5 gram molecule of H2SO4 are there in 49 g....

Hope This Helpful to U....

Mark as a Brilliant..

Answer 2

A mole of a substance is defined as “the mass of the substance” contained in the body or an element.  

Sulphuric Acid is given by $\mathrm{H}_{2} \mathrm{SO}_{4}$ and so there are 2 atoms of H, 1 atom of S and 4 atoms of O which is a total of 7 atoms.

We also know that 1 mole of sulphuric acid = 98gm.  

So, 98gm = 1 mole

We are given that the “mass of sulphuric acid” as 49 gm.

So, 49gm = 0.5 mole

$=0.5 \times 6.023 \times 10^{23} \text { moles }=3.011 \times 10^{23}\ moles$.