Chemistry, asked by atharvswami9373, 10 months ago

How many moles H2SO4 are present in 4.9 gm H2SO4

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Answered by sony123bunny
0

Answer:

Explanation:

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How many moles are present in 4.9g of H2SO4

Comments (1) Report by Ayushi619 25.06.2018

barish95644

plz mark me as brainiest

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barish95644

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see... I mole of sulfuric acid= 98 gm

98 gm corresponds to 1 gram molecule of the given compound (h2so4)

1 gm corresponds to 1/98 gram molecules

4.9 gm corresponds to 4.9/98 gram molecules = 1/20 gram molecules = 0.05 gram molecules (Ans.)

Answered by TheUnsungWarrior
0

Answer:

Moles = 0.05

Explanation:

Given;-

          Weight, w = 4.9 g

Molecular Weight, MW = H₂SO₄

                                       = 1×2 + 32 + 16×4

                                       = 98 u

Now, we know by formula that;-

       Moles = Weight / Molecular Weight

Putting the given values in the question we get;-

       Moles = 4.9/ 98

       Moles = 1/20

       Moles = 0.05

Extra Information:

A moles is comprised of Na ( Avogadro number ) of entities. The entities can include atoms, molecules, ions, etc.

1 Avogadro , Na = 6.022 × 10²³

Hope it helps! ;-))

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