How many moles H2SO4 are present in 4.9 gm H2SO4
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Answer:
Explanation:
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How many moles are present in 4.9g of H2SO4
Comments (1) Report by Ayushi619 25.06.2018
barish95644
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barish95644
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see... I mole of sulfuric acid= 98 gm
98 gm corresponds to 1 gram molecule of the given compound (h2so4)
1 gm corresponds to 1/98 gram molecules
4.9 gm corresponds to 4.9/98 gram molecules = 1/20 gram molecules = 0.05 gram molecules (Ans.)
Answer:
Moles = 0.05
Explanation:
Given;-
Weight, w = 4.9 g
Molecular Weight, MW = H₂SO₄
= 1×2 + 32 + 16×4
= 98 u
Now, we know by formula that;-
Moles = Weight / Molecular Weight
Putting the given values in the question we get;-
Moles = 4.9/ 98
Moles = 1/20
Moles = 0.05
Extra Information:
A moles is comprised of Na ( Avogadro number ) of entities. The entities can include atoms, molecules, ions, etc.
1 Avogadro , Na = 6.022 × 10²³
Hope it helps! ;-))