Question

How many moles of 0 are present
of H3 Po4u
(At wt
in 4.9
P=31
of
g
0=16
& H=1​

Answer 1

H3PO4

H = 1 g

O = 16 g

P = 31 g

Mass of Oxygen in H3PO4 = 16 × 4 = 64 g

Molar mass of Oxygen = 16 g

No. of moles = Mass given / Molar mass

☛ no. of moles = 64/16

☛ no. of moles = 4

Answer 2

H3 Po4u ...

The answer was..

H=1g,O=16g,P=31g

The mass of oxygen in H3PO4 = 16×4=64g

Molar Mass of oxygen = 16g

No. of moles = Mass Given or Molar Mass

No. of moles = 64÷16 = 4

So the answer will be -4...