How many moles of 02 gas exerts pressure of 2atm on the walls of 4.1l container at 127 c
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How many moles of 02 gas exerts pressure of 2atm on the walls of 4.1l container at 127 c .
P = 2 atm
V = 4.1 L
T= 127°C
= 127 + 273 K
= 400 K
R = 0.0821 atm K-¹ mol -¹
n = PV / RT
= 2×4.1 / 0.0821 × 400
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We can say that 0.25 mole of O2 gas exerts pressure of 2 ATM on the wall of 4.1 l container at 127 c .
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