How many moles of 224 co (oxalate ions) can be completely oxidized by one mole of 4 mno ions in acidic medium?
Answers
Answered by
0
The balanced redox reaction can be written as:
2 MnO4- + 5 C2O42- + 16 H+ → 2 Mn2+ + 10 CO2 + 8 H2O.
The equation shows that 2 moles of manganate ions oxidixe 5 moles of oxalate ions.
So, 1 mole of manganate ions will oxidize (5/2) = 2.2 moles of oxalate ions.
2 MnO4- + 5 C2O42- + 16 H+ → 2 Mn2+ + 10 CO2 + 8 H2O.
The equation shows that 2 moles of manganate ions oxidixe 5 moles of oxalate ions.
So, 1 mole of manganate ions will oxidize (5/2) = 2.2 moles of oxalate ions.
sneha2006:
hi
hii
hi
hwru
fine n u
fine
Similar questions