Question

How many moles of Ag are in 43.6 grams of Ag₂O?

Answer 1

Answer:

(43.6 g Ag2O) / (231.7358 g Ag2O/mol) x (2 mol Ag / 1 mol of Ag2O) = 0.376 mol Ag

Explanation:

1 grams Ag to mol = 0.00927 mol

10 grams Ag to mol = 0.09271 mol

50 grams Ag to mol = 0.46353 mol

100 grams Ag to mol = 0.92706 mol

200 grams Ag to mol = 1.85411 mol

500 grams Ag to mol = 4.63529 mol

1000 grams Ag to mol = 9.27057 mol

Answer 2

Given:

Ag are in 43.6 grams of Ag₂O

Find:

How many moles

Solution:

1 grams Ag to mol = 0.00927 mol

10 grams Ag to mol = 0.09271 mol

50 grams Ag to mol = 0.46353 mol

100 grams Ag to mol = 0.92706 mol

200 grams Ag to mol = 1.85411 mol

500 grams Ag to mol = 4.63529 mol

1000 grams Ag to mol = 9.27057 mol

(43.6 g Ag2O) / (231.7358 g Ag2O/mol) x (2 mol Ag / 1 mol of Ag2O)

= 0.376 mol Ag