Question

How many moles of AgCI will be produced from 60.0 g of AgNO3

Answer 1

Answer:

AgNO3+HCl gives rise to AgCl+HNO3

Moleculer weight of AgNO3=169

169g of AgNO3 gives 1mole of AgCl

60g of AgNO3 gives x moles of AgCl

x= 60/169 =0.355 moles

Approximately 60 g of AgNO3 gives 0.4 moles of AgCl.