Question

how many moles of agcl will be formed if 10 gram each of KCL and NaCl react with excess of silver nitrate​

Answer 1

Answer:

When Solution of silver nitrate (AgNO3) is added to the aqueous solution of sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed that is indicated by the following balanced chemical reaction.

AgNO3 + NaCl → AgCl + NaNO3

In this situation,

NaCl = 10 gm

Number of mole in NaCl = 10/58.44 = 0.17 mol

Therefore, we know that by

Mole concept, Moles of NaCl / S.C. of NaCl = Moles of AgCl / S.C. of AgCl

=> 0.17 / 1 = Moles of AgCl / 1

=> 0.17 mol = Moles of AgCl

And

When solution of potassium chloride when mixed with silver nitrate solution, an insoluble white substance is formed. A balanced chemical reaction given by,

KCl(aq) + AgNO3(aq) → KNO3(aq) + AgCl (s)

In this situation,

KCl = 10 gm

Mole of KCl = 10 / 74.55

= 0.13 mol

We know that

By Mole concept

Moles of KCl / S.C. of KCl = Moles of AgCl / S.C. of AgCl

=> 0.13 / 1 = Mole of AgCl / 1

=> 0.13 mol = Mole of AgCl

Thankyou

By

Aaditya Singh