Question

How many moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminum oxide, Al2O3

Answer 1

Explanation:

Al2O is not a real compound because the Al2 would have a total 6+ charge, whereas oxygen only has a 2-, so it would really be a Al2O ion with a 4+ charge.

If you ran out of room and meant to put Al2O3 (a real neutral charged compound), then you would have 3 moles of O for every 2 of Al, and would then need 2/3 x 1.58 moles of Al = 1.053 moles.

Answer 2

The moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminium oxide, Al2O3 is 1.053 moles.

Given:

1.58 mol of O atoms used to make aluminium oxide, Al2O3.

To Find:

The moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminium oxide, Al2O3.

Solution:

To find the moles of Al atoms needed we will follow the following steps:

As we can see from the formula of aluminium oxide that 2 moles of aluminium are used with 3 moles of oxygen to form Al2O3 oxide.

Now,

3 moles of oxygen require 2 moles of aluminium.

So,

$1 mole \: of oxygen \: require = \frac{2}{3} moles \: of \: aluminium$

$1.58 \: moles \: of \: oxygen \: require \: = \frac{2}{3} \times 1.58 = 1.053 \: moles$

Henceforth, The moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminium oxide, Al2O3 is 1.053 moles.

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