Question

How many moles of al2o3 will be formed when a mixture of 5.4g al and 3.2?

Answer 1

Explanation:

4 Al + 3 O2 ---------> 2 Al2O3

No. of moles of Al = 5.4÷27

= 0.2 mol

No. of mole of O2 = 3.2÷32

= 0.1 mol

3 mol O2 reacts with 4 mol Al

1 mol O2 reacts with 4/3 mol O2

0.1 mol O2 react with 0.133 mol O2

So, O2 is limiting reagent .

So, 0.067 mol O2 is left

So, ( 2/3 × 4/30 ) mol al2o3 is formed

= 4/45 mol al203 is formed.