Question

How many moles of aluminium atoms are present in 12.044*10^23atoms of aluminium?

Answer 1

Answer:

For Helium,

Number of atoms=Number of moles ×6.022×10

23

No of Moles =

6.022×10

23

12.044×10

23

= 2.

Now, atomic mass of He=4

Weight = 2×4 = 8 g