Question

How many moles of aluminium sulphate, Al2(S04)3
will contain 0.24 mole of oxygen atoms?

(1) 2.0 x 10²
(2) 2.0 x 10^-2
(3) 3.0 × 10³
(4) 1.5 × 10^-2​

Answer 1

Answer:

Al = 27

S = 32

O = 16

Al2 (So4) 3 = (27×2) +(32+16)3

= 54 + 48 ×3

= 54 + 144

= 192

now, 192 / 0.24 × 6.022 × 10 -11 ( power)

option , 3.) 3.0 × 10 3

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Answer 2

Answer:

A=27 S=32. O=16 AL2(SO4)3=(27.2) +(32+16).3=54+48.3=54+144=192. 192/0.24.6.022.10-11=3.0.10TO THE POWER3