How many moles of aluminium sulphate, Al2(SO)
will contain 0.24 mole of oxygen atoms?
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14
Answer:
Al = 27
S = 32
O = 16
Al2 (So4) 3 = (27×2) +(32+16)3
= 54 + 48 ×3
= 192
So, 192 / 0.24 × 6.022 × 10^-11
3×10^3 is the answer
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