Chemistry, asked by darrencrawford889, 5 months ago

How many moles of aluminum ions are present in 58.0 mL of a 0.0100 M solution of aluminum sulfate?

Answers

Answered by mukherjeearjun2003

0

Answer:

0.01=n×1000/58

58×0.01×10-³= n

5.8×10-⁵=n

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