Question

How many moles of aluminum oxide will be formed when a mix of 5.4g of al and 3.2 g of oxygen.

Answer 1

From the equation we know that 4Al + 3O2 -> 2Al2O3.

We know that the moles of aluminium = 5.4/27 = 0.1 mole.

Moles of oxygen gas = 3.2/(16*2) = 0.1 mole.

So, from the reaction we get 4 moles of Aluminium reacts with 3 moles of oxygen.

From the equation we know that 0.2 mol of aluminum will react with:

We get that 3/4*0.2 = 0.15 mol of the  oxygen gas.

Consequently 0.1 mol of oxygen will react with:

So, we get that 4/3*0.1=0.13 mol of aluminum.

We can conclude that oxygen is the limiting reagent.

Since we know that 2 moles oxygen gives 3 moles Al2O3 then 0.1 moles of oxygen will give 2/3*0.1= 0.066 of aluminum oxide.

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