Question

How many moles of atoms are present in 7 mole of sulfuric acid, H2SO4? a) 7 x 6 x 1023 b) 7 c) 21 d) ​

Answer 1

Atomic mass of one molecule of H2SO4 is 98 Atomic mass unit.

Atomic mass of one mole of H2SO4 is 98 grams.

So 98 grams of H2SO4 contains 1 mole of H2SO4 molecule i.e., 7 moles atoms.

So, by applying the basic maths, we get

49 grams of H2SO4 contains 1/2 mole of H2SO4 molecule i.e., 3.5 moles atoms.

Hope it helps.

Answer 2

Correct Question:

How many atoms are present in 7 mole of sulfuric acid ?

• 7 × 6.023 × 10²³
• 7
• 21
• 49 × 6.023 × 10²³

Calculation:

We know that :

• 1 mole of any substance contain Avagadro number of molecules.

• So, 1 mole of sulphuric acid will have 6.023 × 10²³ molecules.

Now, each molecule of H2SO4 have 7 atoms.

• So , total number of atoms:

$= 7 \times 7 \times 6.023 \times {10}^{23}$

$\boxed{ = 49\times 6.023 \times {10}^{23} }$

$= 2.95\times {10}^{25} \: atoms$

So, option d) is correct ✔️