How many moles of atoms contained in 3.4×1024 atoms of Fluorine
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Answer:
5.6 moles are present in 3.4×10^24 atoms.
Explanation:
1 mole of calcium has 6.023×10^23 atoms.
1 mole→ 6.023×10^23
x→ 3.4×10^24
⇒x= 34×10^23 / 6×10^23
=5.6 moles
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