How many moles of Ba3(PO4)2 can be formed when 1.3 moles of BaCO3 react with 2.5 moles of FePO4?
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3BaCO3 + 2FePO4 ----> Ba3(PO4)2+ Fe2(CO3)3 3 mole 1 mol 3 mol BaCO3 ---- 1 mol Ba3(PO4)2 1.3 mol BaCO3 ---- X mol Ba3(PO4)2 X = (1.3×1)/3 = 0.43 mol :)
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