Question

how many moles of Barium carbonate will contain 1.5 moles of oxygen atoms

Answer 1

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》 SOLUTION ::-

Barium carbonate ( BaCo3 ) = 197 gm.

let x be the no of moles of BaCo3

then,
3 mole of O contain in 1 mole of BaCo3

1 mole of O = 1/3 mole of BaCo3

so, 1.5 mole of O = 1/3 ×1.5 mole of BaCo3

hence, no of moles of BaCo3 = 1/3 ×1.5 =
0.5 mole.