How many moles of Ca2+ are present in 5.67 moles of calcium phosphate? I"m not sure how to approach the problem.
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☆ 1 mol of Ca3(PO4)2 => contains 3mol Ca
☆ So 5.67 mol Ca3(PO4)2 => ????
☆ n of Ca+ = 5.67× 3 ÷ 1 = 17.01 mol
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