Question

How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2 2.2 mol CaCl2 3.1 mol CaCl2 6.2 mol CaCl2 12.4 mol CaCl2

Answer 1

Answer:

3.1 mol CaCl2

Explanation:

As silver nitrate completely reacts it is the limiting reagent.

2 moles AgNO3 reacts with 1 mole CaCl2

so, 1 mole of AgNO3 will react with 1/2 mole CaCl2

then, 6.2 moles of AgNO3 will react with 1/2 × 6.2 = 3.1 moles of CaCl2