how many moles of calcium hydroxide is required to neutralize 2 moles of h3po2
Answers
What is the number of moles of NaOH required to neutralize a solution of H3PO4 and H3PO2 present in 2 moles each?
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First, let us look at the structure of H3PO4 and H3PO2 (you'll understand why in a minute)
H3PO4:
H3PO2:
As we know, NaOH is a base and it neutralizes acids to give a salt and water.
We also know that acids are those which easily give away a H + ion.
In case of H3PO4, there are 3 H + ions which can be shared (from all three OH groups). Which means that it's basicity is 3.
However, in case of H3PO2, there is only one OH group and hence only one H + ion can be given out (the hydrogen bonded directly to phosphorus can't be given out as a H + ion). So, it's basicity is only 1.
But what does basicity mean? Basicity is the number of moles of H + ions given out by one mole of the acid. (Or the number of H + ions given out by one molecule of acid).
This implies that one mole of H3PO4 can give out 3 moles of H + ions and hence it can reach with 3 moles of NaOH. So two moles of H3PO4 requires 6 moles NaOH
Similarly, one mole of H3PO2 can give out 1 mole of H + ions and hence can reach with 1 mole of NaOH. So two moles H3PO2 requires 2 moles NaOH.
Hence, the total number of moles of NaOH required is 6+2 = 8.
Answer:
You need 3 mol of sodium hydroxide to neutralize 1 mol of phosphoric acid.
Explanation:
The balanced equation for the reaction is
3NaOH
+
H
3
PO
4
→
Na
3
PO
4
+
3
H
2
O
Phosphoric acid
H
3
PO
4
is a triprotic acid. It has three acidic hydrogen atoms.
Thus, one molecule of phosphoric acid will need three formula units of sodium hydroxide, and
One mole of phosphoric acid will need three moles of sodium hydroxide.
This is what the balanced equation tells us:
3 mol of
NaOH
reacts with 1 mol of
H
3
PO4.
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