Question

How many moles of calcium hydroxide must be dissolved to produce 250 ml of an aqua solution of PH 10.48.
Assume complete dissociation .​

Answer 1

$\huge\red{\boxed{\blue{\mathcal{\overbrace{\underbrace{\fcolorbox{blue}{aqua}{\underline{\red{ANSWER}}}}}}}}}$

Explanation:

$\huge\red{\boxed{\blue{\mathcal{\overbrace{\underbrace{\fcolorbox{blue}{aqua}{\underline{\red{THANKS PLZ}}}}}}}}}$

Answer 2

♥️♥️ $\huge\red{A}\pink{N}\orange{S}\green{W}\blue{E}\gray{R}$ ♥️♥️

• We know that

pH+pOH=14

So, pOH=(14−10.65)=3.35

[OH−]=10−3.35=10−4×100.65=4.47×10−4M

One molecule of Ca(OH)2 furnishes 2OH− ions

Hence concentration of

Ca(OH)2=24.47×10−4=2.235×10−4M

No. of moles in 250mL=42.235×10−4=5.58×10−5 ..

✌️ MARK ME BRAINLIST ✌️