Question

how many moles of carbon are needed to react with 525 g of hematite​

Answer 1

Answer:

Fe2O3 + C -> Fe + CO2

Explanation:

Now, we have 3 oxygens and we need 6:

2Fe2O3 + C -> 2Fe + 3CO2

Now we need to balance the carbons:

2Fe2O3 + 3C -> 2Fe + 3CO2

Looks like 3 moles of C for 2 moles of Fe2O3. Just figure out how many moles you have and multiply by 3/2.

Answer 2

Given: Weight of hematite = 525 grams

To find: Number of moles of carbon

Solution:

• Haematite is the ore of iron and is present as an oxide of iron. Fe₂O₃ is haematite.

• When haematite reacts with carbon, it forms iron and carbon dioxide.

        2Fe₂O₃ +3C → 4Fe + 3CO₂

• Two moles of Fe₂O₃ react with three moles of carbon to form four moles of iron and three moles of carbon dioxide.

• The molecular mass of haematite =  159

• Moles is the ratio of the mass of the compound taken to the molecular mass of the compound.

• Number of moles of haematite in 525 grams = mass of the haematite / molecular mass of haematite

         = 525/159 = 3.3

• 1 mole of Fe₂O₃ reacts with 3/2 CO₂

• 3.3 moles of Fe₂O₃ reacts with 3/2×3 = 4.5

Therefore, 4.5 moles of carbon are needed to react with 525 grams of haematite.