How many moles of carbon are present in 60 g glucose
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Answer:
24g
Explanation:
Formula of glucose is C6H12O6
Molar mass=12×6+1×12+16×6
=72+12+96
=180
Mass of carbon=72
Moles of carbon present in 60 g = 72/180×60
=72/3
=24g
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