Question

How many moles of CH4 and required to froduce 88 gr of Co2 after combustion in chemistry class11

Answer 1

$\bigstar \sf \large \underline{\underline{Answer:-}}$

❥︎ 2Moles.

$\\ \\ \bigstar \sf \large \underline{ \underline{Solution:-}}$

Acc to question,

The stereometric equation is :-

$\\ \\ \sf \ \: CH_4 (g) + 2O_2 (g) \longrightarrow CO_2 (g) + 2H_2 O (l)$

The Molecular mass of CO2 :-

➪ 12+2(16) = 44g.

From the reaction we can say that,

On complete combustion,

1 Mole of methane ➝ 44g (1 mole ) of CO2

? Moles of methane ➝ 88g of CO2.

Therefore,Moles of CH4 required to produce 88g of CO2 are :-

$\\ \\ \implies \sf 88 \times \frac{1}{44} \\ \\ \implies \sf \pink{\boxed{ \underline{2 \: moles.}}}$

Know More:-

❥︎ Molar Mass = m / n .

Where,

m= Mass of substance in grams

n= No of moles.

❥︎ Combustion is a rapid chemical process such as oxidation that produces heat and usually light.

❥︎ 1 Mole = 6.022 × 10^23 of any chemical unit such as atoms,ions,etc.

❥︎ Molar mass of Methane = 16g.

❥︎ Molar mass of O2 = 32g.

❥︎ Molar mass of H2O = 18g

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HOPE IT HELPS !