Question

how many moles of Chromium (III) Sulfide will you have if you react 10.0 grams of Chromium (III) Oxide with excess Hydrogen Sulfide?
Cr2O3 + 3H2S --> Cr2S3 + 3H2O​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

1 moles

Cr2O3(s) + 3 H2S(g) ⟶ Cr2S3(s) + 3 H2O(l)

Cr2O3(s) + 3 H2S(g) ⟶ Cr2S3(s) + 3 H2O(l) The flow for this problem will be like this:

Cr2O3(s) + 3 H2S(g) ⟶ Cr2S3(s) + 3 H2O(l) The flow for this problem will be like this:Mass of Cr2S3 (molar mass of Cr2S3) → Moles of Cr2S3 (mole-to-mole comparison) → Moles of Cr2O3