Question

How many moles of Cl2 will be required to liberate all of the bromine from 8 moles of CrBr3?

Answer 1

12 moles of Cl₂

Explanation:

Balance reaction:

3Cl₂ + 2CrBr₃ → 3Br₂ + 2CrCl₃

3 moles of Cl₂ is required to liberate all the Br₂ from the 2 moles of CrBr₃

If 8 moles of CrBr₃ is there then,

3 moles of Cl₂ → 2 moles of CrBr₃

∴ x moles of Cl₂ → 8 moles of CrBr₃

∴ x = 8 × 3/ 2

x = 12 moles of Cl₂