Question

How many moles of CO2 are in 79g of C3H8? Assuming O2 is available in access.

Answer 1

Answer:

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Answer 2

Answer:

79 g of C3H8 contains 79/44 = 1.79 moles

C3H8 +O2 —-> 3CO2 + 4H2O

From reaction we know,

1 mole C3H8 liberates 3 mole CO2

So Let 79g / 1.79 moles liberate X mole Co2.

Then x = 1.79 mole C3H8 * 3mole Co2/1 mole C3H8

X = 1.79 * 3 = 5.38 moles of CO2.

5.38 moles of CO2 is released.