Question

how many moles of CO2 will left it 10'21 molecules are removed from 513.07 mg of CO2​

Answer 1

Explanation:

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Answer 2

Answer:

To find:

How many moles of co2 will left if 10²¹ molecules are removed from 513.07mg of CO2.

Calculation:

Moles of CO2 (carbon dioxide) in 513.07 mg :

$\rm \therefore \: no. \: of \: moles = \dfrac{given \: mass}{molar \: mass}∴no.ofmoles= </p><p>molarmass</p><p>givenmass</p><p> </p><p> </p><p></p><p>\rm \implies \: no. \: of \: moles = \dfrac{0.513}{44}⟹no.ofmoles= </p><p>44</p><p>0.513</p><p> </p><p> </p><p></p><p>\rm \implies \: no. \: of \: moles = 0.0116⟹no.ofmoles=0.0116$

Now, number of moles associated with 10²¹ molecules of CO2 :

$\rm \therefore \: no. \: of \: moles = \dfrac{no. \: of \: molecules}{avagadro \: no.}∴no.ofmoles= </p><p>avagadrono.</p><p>no.ofmolecules</p><p> </p><p> </p><p></p><p>\rm \implies\: no. \: of \: moles = \dfrac{ {10}^{21} }{6.023 \times {10}^{23} }⟹no.ofmoles= </p><p>6.023×10 </p><p>23</p><p> </p><p>10 </p><p>21$

$\rm \implies\: no. \: of \: moles = 0.167 \times {10}^{ - 2}⟹no.ofmoles=0.167×10 </p><p>−2</p><p> </p><p></p><p>\rm \implies\: no. \: of \: moles = 0.0016⟹no.ofmoles=0.0016</p><p></p><p>So, number of moles left :</p><p></p><p>\rm moles \: left = 0.0116 - 0.0016molesleft=0.0116−0.0016</p><p></p><p>\implies\rm moles \: left = 0.01⟹molesleft=0.01$

So, number of moles left is 0.01