Question

how many moles of copper are presnet in 148.2g Ca(OH)2

Answer 1

Answer:

2 moles.

Logic:

no of moles $\\\tt \longrightarrow$ $\\\tt \dfrac{mass\ of\ substance}{molar\ mass}$

Steps:

Mass of $\\\tt Ca(OH)_2$ = Mass of Ca + 2 (Mass of O) + 2(Mass of H)

= 40 amu + 32 amu + 2amu

= 74 amu.

Moles of $\\\tt Ca(OH)_2$  will be

$\dfrac{148.2}{74} \\\tt \\\tt = 2.0027$