Question

How many moles of each solute is required to prepare the following solutions?

1 L of a 2.5 M HCl solution

Answer 1

Answer:

Moles of solute = Molarity * Volume

2.5M HCl * 0.5 L = 1.25 moles of HCl

Explanation:

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Answer 2

1.25 moles of HCl

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