Question

how many moles of electron are present in 0.5 moles NH3?​

Answer 1

Answer:

0.5 mole of Nitrogen

1 mole of N=14 gram

0.5 mole N=0.5×14

=7gram

=

2

1

mole

=

2

1

×6.022×10

23

atoms

=3.011×10

23

atoms.

(c) 8 gram O =?

16 gram of O =1mole

1 gram of O =

16

1

mole

8 gram of O =

16

1

×8=

2

1

=

2

1

×6.022×10

23

atoms

=3.011×10

23

atoms.

Same as in O,S mole of nitrogen.

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Answer 2

0.5 mole of Nitrogen

1 mole of N=14 gram

0.5 mole N=0.5×14=7gram

= 21 mole

=21 ×6.022×10 atoms

=3.011×10 23 atoms.

(c) 8 gram O =?

16 gram of O =1mole

1 gram of O = 161 mole

8 gram of O = 161 ×8= 21

= 21 ×6.022×10 23 atoms=3.011×10 23 atoms.

Same as in O,S mole of nitrogen.