Question

how many moles of electron will contains weigh 500gm​

Answer 1

Solution:

Mass of one electrons = 9.1 * 10^-31 kg

∵ Number of electrons in ½ kg = ½ ÷ 9.1 * 10^-31 kg

Number of electrons = Number of moles * Avogadro's Number

Number of moles = Number of electrons ÷ Avogadro's Number

Number of moles of electrons = ½ ÷ 9.1 * 10^31 kg ÷ 6.023 × 10²³

Number of moles of electrons = 0.9 × 10^8

Therefore, Required Number of electrons is 0.9 × 10^8 .

Answer 2

Answer:-

Explanation:-

To Find :-

Number of electrons.

Solution:-

The mass of an electron is 9.1 × 10⁻³¹ kg

Therefore number of electrons in ½ kg = ½ /(9.1 × 10⁻³¹) electrons

=  ½ ÷ 9.1 × 10⁻³¹ kg

Number of particles in 1 mole = 6.023 × 10²³ (Avagadro’s constant)

Number of moles = Number of electrons/ Avagadro’s constant

= ½ × 9.1 × 10⁻³¹/6.023 × 10²³

= 0.9 × 10⁸ electrons

Hence, Number of electrons is 0.9 × 10⁸ .