Question

how many moles of electrons are added when 2.5 mole cr2o7-2 reduce in cr+3​

Answer 1

Answer:

15 moles of elements are added when 2.5 mole Cr2O72– reduced in Cr3+.

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Answer 2

Answer:

When 2.5 moles of cr2o7-2 are reduced to cr+3, 15 moles of electrons are added.

Explanation:

When 2.5 mole Cr2072- is reduced in Cr3+, electrons are added in moles.

• Firstly let us see the equation for it.

Cr207 2- + 14H+ + 6e -> 2Cr3+ + 7H20

• By this above equation of the following equation we get to know that,

For 1 mol of Cr207-2, 6 electrons are added to reduce it in Cr+3.

• So, for 2.5 mol the moles of electrons added are as follows :

2.5 × 6 = 15 moles of electrons

Therefore, When 2.5 moles of cr2o7-2 are reduced to cr+3, 15 moles of electrons are added.

OR

• In redox reactions, the phrase n factor or valency factor is employed. It's a term that describes how many electrons per atom are gained or lost during a process.

n factor = 2 × (3) = 6 (for2Cr6 -> 2Cr*3)

We know that,

Number of equivalent = (nfactor × no.of moles)

= (6 × 2.5)

= 15 moles.

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