how many moles of electrons are passed when 0.8 ampere of current is passed for 1 hour through molten CaCl2.
Answers
Answered by
3
Answer:
Explanation:
it/96500 = moles of e
0.8*3600 / 96500 = moles of e
2880 / 96500 = 0.029
moles of e = 0.029
Answered by
2
Given:
0.8 ampere current is passed for 1 hour through molten CaCl2
To find:
How many moles of electrons are passed?
Solution:
From given, we have.
0.8 ampere current is passed for 1 hour through molten CaCl2
The charge is given by the formula,
Q = It
Q = 0.8 × 1 × 60 × 60
Q = 2880 C
The number of moles of eletrons,
n = Q/96500
n = 2880/96500
n = 0.02984 = 2.984×10^{-2} moles
Therefore, the number of moles of electrons are passed are 2.984×10^{-2} moles
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