how many moles. of electrons are required toreduce 1mol of MnO-4 toMn2+
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5moles of electrons are required In the reduction of 1 mol MnO–4 to Mn2+, there is net gain of 5e–
MnO4 + 5e– + 8H+ → Mn2+ + 4H2O
5F = 5 x 96500 = 482500 C
MnO4 + 5e– + 8H+ → Mn2+ + 4H2O
5F = 5 x 96500 = 482500 C
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