How many moles of electrons will together
contribulds to
the charge of 289500 coulomb?
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Answer:
1 mole of electrone contribute to the charge of 1 F = 96500 C
1 C charge =
96500
1
F
289500 C charge =
96500
1
289500 F
=3F
3 mole of electrone will together contribute to the charge of 289500 C
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