How many moles of Epsom Salt (MgSO4) would 27.8 grams be?
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Explanation:
Actually, the compound MgSO4 is not Epsom salt. Epsom salt is the heptahydrate : MgSO4·7H2O. The molar mass of the heptahydrate is 246.47 g/mol, while the molar mass of MgSO4 is 120.37 g/mol. Therefore, if you really have Epsom salt, in order to prepare a bath containing 4.60 moles of Epsom salt, you need
m = nM = 4.60\text{ mol}·246.47\text{ g/mol} = 1133.8m=nM=4.60 mol⋅246.47 g/mol=1133.8 g .
If you have anhydrous MgSO4, you will need:
m = nM = 4.60\text{ mol}·120.37\text{ g/mol} = 553.7m=nM=4.60 mol⋅120.37 g/mol=553.7 g and water, of course.
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