how many moles of ethane are required to produce 44g of CO2 after the combustion of ethane????
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Answered by
13
Reaction for the combustion of the Ethane is ⇒
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2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
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From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
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Answered by
31
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By writing the combustion equation
2CH3_CH3 +7O2----->4CO2 +6H2O
So basicalythe ratio between moles of ethane and carbon dioxide is 1:2
1 mole of ethane---->2moles of CO2
Masses of one mole of each
12×2+6×1 grams of ethane----->2(12+16×2) g CO2
30 grams of ethane--->88g CO2
X grams of ethane---->44g CO2
X=(30×44)/88= 15 grams
No. Of moles = mass(in grams)/molecular mass of ethane
No of moles =15/(12×2)+6×1 = 0.5 molesm
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gd afternoon
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