Question

How many moles of ethane id required to produce 88g of CO2 after combustion​

Answer 1

Explanation:

1 mole ethane is required to produce 88g of CO2.

Answer 2

Given:

Mass of $\[C{O_2}\]$ produced $=88g$

To Find: Number of moles of ethane required to produce 88g of CO2 after combustion​

Solution:

The reaction of combustion of ethane can be given as:

$\[2{C_2}{H_6} + 7{O_2} \to 4C{O_2} + 6{H_2}O + \Delta \]$

From the above reaction,

2 moles of ethane produces 4 moles of $\[C{O_2}\]$

Therefore,

1 mole of ethane will produce 2 moles of $\[C{O_2}\]$

The mass of 2 moles of $\[C{O_2}\]$ will be

$\[Mass = Moles \times {\rm M}olar\,mass\]$

$\[Mass = 2 \times 44\,g\]$

$\[Mass = 88\,g\]$

Hence, the number of moles of ethane required to produce $\[88\,g\]$ of $\[C{O_2}\]$ is 1 mole.